Let, the event of getting head in a coin be H and the event of getting 5 in a die be F.
Then, P(H) = \(\frac12\) and P(F) = \(\frac16\)
To find, P(H∩F)
Here, H and F are independent events.
Then, by formula
P(H∩F) = P(H) x P(F)
= \(\frac12\) x \(\frac16\)
= \(\frac1{12}\)
The probability of getting head in coin and getting 5 in dice is \(\frac1{12}\)