Area of cylinder A= a1 =0.5 m2
Effort applied A = f1 = ?
area of cylinder B = a2 = 10 m2
load to be balanced on B = F2 = 1000 N
According to pascal's law,
Pressure at A = pressure at B
\(\frac{f1}{a1}=\;\frac{f2}{a2}\)
F1 = (1000 * 0.5 )/ 10
f1 = 50 N
Thus, 50 N effort is to be applied on cylinder A to balance the load of 1000 N on cylinder B.