Here,
9a - 10 x 3a + 9 = 0
or, (3a)2 - 10 x 3a + 9 = 0
Let, 3a = x, we get
X2 - 10x + 9 = 0
x2 - 9x -x + 9 = 0
or, x(x - 9) - 1(x - 9) = 0
or, (x - 9) (x - 1) = 0
Now, substituting the value of x, we get
(3a - 9) (3a - 1) = 0
Either, 3a - 9 = 0 or, 3a = 9 or, 3a = 32 or, a = 2 |
Or, 3a - 1 = 0 or, 3a = 1 or, 3a = 30 or, a = 0 |
Therefore a = 0 or 2.