here,
from the given diagram
for piston A and piston B ,
Force at A F1 =250 N
AREA of A A1 = 20 cm2
Force at B F2 = 375N
area of B A2 = ??
Using pascals law,
\(\frac{F1}{A1}=\;\frac{F2}{A2}\)
\(\frac{250}{20}=\;\frac{375}{A2}\)
\(A2=\frac{375\;\ast\;20\;}{250}\)
A2 = 30 cm2
Similarly , for piston A and C
Force at C F3 = ?
Area of C A3 = 10cm2
Again using the same pascal's formula . weget ,
\(F3=\frac{250\;\ast\;10\;}{20}\)
F3 = 125 N
Thus area of piston B is 30 cm2and force at piston C is 125N.