Given,
heat supplied Q = 600 J
mass m = 0.02 kg
raise in temperature dt = ?
specific heat capacity of water s = 4200 J/kg°C
here,
Q= msdt
600 = 0.02 * 4200 * dt
dt = 600 / ( 0.02 * 4200 )
= 7.14°C
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if 600 J is added to 20 gm water, what is rise in temperature ?
Given,
heat supplied Q = 600 J
mass m = 0.02 kg
raise in temperature dt = ?
specific heat capacity of water s = 4200 J/kg°C
here,
Q= msdt
600 = 0.02 * 4200 * dt
dt = 600 / ( 0.02 * 4200 )
= 7.14°C
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