Given,
heat supplied Q = ?
temperature raised dt = 80°C
mass of pan m = 0.5 kg
specific heat capacity s = 480 J/ kg°C
By using heat equation,
Q = m*s* dt
Q= 0.5 * 480 * 80
Q = 19200 J
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How much heat is required to increase temp of frying pan by 80°C if the mass of the pan is 0.5 kg and its specific heat is 480 J/kg°C
Given,
heat supplied Q = ?
temperature raised dt = 80°C
mass of pan m = 0.5 kg
specific heat capacity s = 480 J/ kg°C
By using heat equation,
Q = m*s* dt
Q= 0.5 * 480 * 80
Q = 19200 J
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