Given,
amount of heat Q =70800 J
difference in temp dt = 110 - 40
= 70 °C
specific heat capacity of iron is 470 J/ kg°C
mass of iron ball m = ?
by the formula,
m = Q/ (s*dt)
m= 70800/ 32900
= 2.15 KG.
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Calculate the mass of an iron, Q 70800 J, 40°C to 110°C.
Given,
amount of heat Q =70800 J
difference in temp dt = 110 - 40
= 70 °C
specific heat capacity of iron is 470 J/ kg°C
mass of iron ball m = ?
by the formula,
m = Q/ (s*dt)
m= 70800/ 32900
= 2.15 KG.
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