Given ,
heat supplied Q = 2100 J
mass m = 1 kg,
initial temp t1 = 15 °C
specific heat of mercury s = 140 J/kg°C
final temperature t2 = ??
by the formula,
Q = msdt
Q= ms(t2-t1)
2100 = 1*140 ( t2 - 15)
15 = t2 -15
t2 = 15 +15
= 30 °C
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Calculate the final temp when 2100 J of heat is given to mercury of mass 1 kg at 15°C. mercury specific heat capacity is 140 J/ kg °C.
Given ,
heat supplied Q = 2100 J
mass m = 1 kg,
initial temp t1 = 15 °C
specific heat of mercury s = 140 J/kg°C
final temperature t2 = ??
by the formula,
Q = msdt
Q= ms(t2-t1)
2100 = 1*140 ( t2 - 15)
15 = t2 -15
t2 = 15 +15
= 30 °C
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