Here mass m = 1 kg
specific heat capacity of the water = 4200 J/ kg°C
difference in temperature = 70 - 40 = 30°C
We have,
Q=MSDT
q = 1 * 4200 * 30
= 12600 j
THUS, the amount of energy released is 126000 J
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Calculate heat energy when, 1 kg m of water at 70°C reduced to 40°C.
Here mass m = 1 kg
specific heat capacity of the water = 4200 J/ kg°C
difference in temperature = 70 - 40 = 30°C
We have,
Q=MSDT
q = 1 * 4200 * 30
= 12600 j
THUS, the amount of energy released is 126000 J
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