Given, F1 = 100 N
F2 = 2000N
A2 = 4m2
A1 = ?
According to pascal's law,
pressure at small piston =pressure at large piston
\(\frac{F1}{A1}=\;\frac{F2}{A2}\)
A1 = 400/2000
A1 = 0.2 m2
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An effort 100N can rise load of 2000N in hydraulic press. Calculate area of a small piston. Area of large piston is 4m^2.Write application of hydraulic press.
Given, F1 = 100 N
F2 = 2000N
A2 = 4m2
A1 = ?
According to pascal's law,
pressure at small piston =pressure at large piston
\(\frac{F1}{A1}=\;\frac{F2}{A2}\)
A1 = 400/2000
A1 = 0.2 m2
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