Given ,
dt = 15°C
m = 5 kg
s = 234 J/ kg°C
Q = ?
we know that, Q2 = msdt
= 5 * 234 *15
17550 J
SIMILARLY for steel,
Q = 17550 J
m = 5 kg
s = 447 J/ kg°C
dt = ?
Q= msdt
17550 = 5 * 447 * dt
dt = 7.85
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Amount of heat to increase 15°C temp, 5 kg silver. If same supplied to silver, calculate change in temp. specific heat capacity of silver = 234 J/ kg°C and wsteel = 447 J/kg°C
Given ,
dt = 15°C
m = 5 kg
s = 234 J/ kg°C
Q = ?
we know that, Q2 = msdt
= 5 * 234 *15
17550 J
SIMILARLY for steel,
Q = 17550 J
m = 5 kg
s = 447 J/ kg°C
dt = ?
Q= msdt
17550 = 5 * 447 * dt
dt = 7.85
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