Here,
initial temp = 4°C
Amount of heat Q= 2016 K J
= 2016 * 1000 J
= 2016000 J
mass of water m = 20 litres
= 20 kg
specific heat capacity (s) = 4200J/ kg°C
difference in temp = ?
We have,
Q=msdt
dt = Q/ms
dt = 2016000 / 84000
dt = 24°C
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A person heats 20l of water at 4°C with 2016 kJ. Rise in temp ?
Here,
initial temp = 4°C
Amount of heat Q= 2016 K J
= 2016 * 1000 J
= 2016000 J
mass of water m = 20 litres
= 20 kg
specific heat capacity (s) = 4200J/ kg°C
difference in temp = ?
We have,
Q=msdt
dt = Q/ms
dt = 2016000 / 84000
dt = 24°C
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