Let, AB be the height of a man, CD be the height of a tree,
AE = BD be the distance between the man and the tree,
and CAE is the angle of elevation of the top of the tree.
Then, by the question
ED = AB = 1.5m
CD = 41.5m, CAE = 45° ,BD = ?
Here, CE = CD - ED = 41.5m - 1.5m = 40m
In right angled triangle CEA
Tan 45° = \(\frac{CE}{AE}\)
or, 1 = \(\frac{40m}{BD}\)
or, BD = 40m
Therefore, the distance between the man and the tree (BD) = 40m