Solution:
Here, CF = CD - FD
= 25 m - 13 m
= 12 m
Now, in the right angled triangle ΔCFA,
tan(45°) = CF/AF
Or, 1 = 12m/BD
Or, BD = 12 m
∴ The distance between the house and the temple is BD = 12 m
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The heights of house and temple are 13 m and 25 m respectively. If a man observes the roof of a temple he finds the angle of depression 45°, find the distance between the house and the temple.
Solution:
Here, CF = CD - FD
= 25 m - 13 m
= 12 m
Now, in the right angled triangle ΔCFA,
tan(45°) = CF/AF
Or, 1 = 12m/BD
Or, BD = 12 m
∴ The distance between the house and the temple is BD = 12 m
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