The earth having the mass 6x1024 Kg revolves around the sun of mass 2x1030 Kg in a circular orbit of radius 1.5x1011 m. Calculate the force of attraction between them (G = 6.67x10-11 Nm2/Kg2).
1 Answer
Here,
Mass of the sun (m1) = 2x1030kg
Mass of the earth (m2) = 6x1024kg
Distance between the centeres of the earth and the sun (d) = 1.5 x 1011m
Force of attraction (F) = ?
According to the newtons law of gravitation,
\(F=\frac{G\times m_1\times m_2}{d^2}\)
\(=\frac{6.67\times10^{-11}\times2\times10^{30}\times6\times10^{34}}{{(1.5\times10^{11})}^2}\)
\(=3.56\times10^{22}N\)
Hence the force of attraction between the sun and the earth is \(=3.56\times10^{22}N\)
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