How wide is the central diffraction peak on a screen 3.5 m behind a 0.01 mm slit illuminated by a 500 nm light source?
1 Answer
Solution
Given,
The width of slit (d) = 0.01 mm = 10-5 m,
The distance between the slit and the screen (D) = 3.5 m,
The wavelength of light used (λ) = 400 nm = 500×10-9 m,
Now, the width of the central diffraction peak is given by
\(x=\frac{2\lambda D}d\),
\(=\frac{2\times500\times10^{-9}\times3.5}{d10^{-5}}\)
= 0.35 m.
Hence, the required width of the central diffraction peak is 0.35 m
Topics from Physics
Physical Quantities
27
Electricity & Magnetism
48
Motion
8
Measurement
4
Electricity
166
Physical Optics
80
Waves
117
Force
51
Heat
137
Laws of Motion
1
Light
100
Pressure
139
Thermodynamics
1
Related Questions