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Check dimensionally the correctness of momentum, p = (2m E/t)^0.5

dimensional analysis and its application
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A student writes an expression of the momentum (p) of a body of mass (m) with total Energy (E) and considers the duration of the time (t) as \(p=\sqrt{2m\frac Et}\). Check its correctness by using dimensional analysis.


1 Answer


Solution:

The given formula is, \(p=\sqrt{\frac{2mE}t}\)

Where,

P is the momentum,
m is the mass,
E is the energy, and
t is the time

The dimension of each terms are as follows:

dimension of momentum, p = [MLT-1],
dimension of mass, m = [M],
dimension of time, t = [T], and
dimension of energy, E = [ML2T2]

Now, substituting the quantities in the above-given relation, we get,

\(\left[MLT^{-1}\right]=\sqrt{\frac{M.ML^2T^{-2}}T}\), because 2 is dimensionless constant

\(=\sqrt{M^2L^2T^{-1}}\)

\(=MLT^{-\frac12}\)

Dimension of LHS Dimension of RHS

So, the formula is dimensionally incorrect.

 

Things to remember from Physical Quantities
  • The four applications of dimensional analysis are:
    • To check the correctness of physical relation.
    • To derive the relation between various physical quantities.
    • To convert the value of physical quantities from one system of units into another system of units.
    • To find the dimensions of constants in the given equation.

  • The correctness of physical relation can be determined by comparing the dimension of the left-hand side (LHS) and the dimension of the right-hand side (RHS)
  • We can use the formula, \(N_2=N_1\left[\frac{M_1}{M_2}\right]^a\left[\frac{L_1}{L_2}\right]^b\left[\frac{T_1}{T_2}\right]^c\)\) to convert unit from one to another system using dimension.

  • Despite the usefulness of dimensions, there are some limitations. They are:
    • The dimensional analysis does not give any information about dimensionless constants.
    • If the quantity depends on more than three other physical quantities having dimensions, the formula cannot be derived.
    • We cannot derive the formula containing trigonometric functions, logarithmic functions, exponential functions, etc. It is best suited for linear functions only.
    • The exact form of a relationship cannot be determined when there is more than one part in any relationship.
    • It gives no information about the physical quantity,

 

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