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A wooden block has 30*20*15cm which floats on density 1g/cm^3. Calculate the height of block that is outside water.

which object displaces water
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A wooden block has 30*20*15cm which floats on density 1g/cm^3. Calculate the height of block that is outside water. 


1 Answer


GIVEN , 

VOLUME OF WOOD vo= 30 * 20 * 15 = 9000cm3

density of wood, do = 0.8 

density of water, dl = 1

volume of liquid displaced vl = ? 

for floaqtation , 

vo do g = vl dl g 

vl = ( vo do )/ dl

vl = 7200 cm3

This volume of wood inside water . 

So, volume of wood outside water = 900 cm-7200 cm3

= 1800 cm3

Part of wood that remains outside = 1800 / 900 

= 1/ 5 

Hence, 1/5 th of its height remains above the water

that is 1/5 *15 

= 3 cm 

therefore, 3 cm of wood remains outside the water. 

 

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