Let, AB be the height of a tower, BC be the length of the shadow of the tower and ACB be the angle made by the sun's rays with the ground.
Then, by the question
AB = 50m, ACB = 30°, BC = ?
Here, in right-angled triangle ABC
Tan 30° = AB/BC
or, \(\frac1{\sqrt3}\) = \(\frac{50m}{BC}\)
or, BC = \(50\sqrt3m\)
or, BC = 5- x 1.732m
or, BC = 86.6m
Therefore, the length of the shadow of the tower is 86.6m.