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Solve the given radical equation for w

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Solve: \(\sqrt{w+4}=\sqrt[3]{64}\)


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Solution:

Here,

\(\sqrt{w+4}=\sqrt[3]{64}\)
Or, \(\sqrt{w+4}=\sqrt[3]{4^3}\)
Or, \(\sqrt{w+4}=4\)

Squaring both sides, we get

\(\left(\sqrt{w+4}\right)^2=4^2\)
Or, w + 4 = 16
Or, w = 16 - 4
Or, w = 12

∴ The value of w is 12.

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