Solution,
Here:
L.H.S = \(\frac{4^{a+2}+4^a}{17\times4^a}\)
= \(\frac{4^a\times4^2+4^a}{17\times4^a}\)
= \(\frac{4^a(16+1)}{17\times4^a}\)
=\(\frac{4^a\times17}{17\times4^a}\)
= 1
= R.H.S, hence proved.
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Prove that: \(\frac{4^{a+2}+4^a}{17\times4^a}=1\)
Solution,
Here:
L.H.S = \(\frac{4^{a+2}+4^a}{17\times4^a}\)
= \(\frac{4^a\times4^2+4^a}{17\times4^a}\)
= \(\frac{4^a(16+1)}{17\times4^a}\)
=\(\frac{4^a\times17}{17\times4^a}\)
= 1
= R.H.S, hence proved.
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