Given,
In triangle ABC,
a = 4cm, b = 6cm and C = 60°
To find, Area of triangle ABC
By formula,
Area of triangle ABC = \(\frac12\) a.b.sinC
= \(\frac12\) x 4cm x 6cm x sin60°
= 12cm2 x \(\frac{\sqrt3}2\)
= \(6\sqrt3\) cm2
= 10.39 cm2
Therefore, the area of triangle ABC is 10.39cm2.