Given primary voltage = 1200 V
Ns = 1/5 of Np
Secondary voltage = ??
We have,
\(\frac{Vp}{Vs}=\frac{Np}{Ns}\)
\(\frac{1200}{Vs}=5\)
Vs = 240 V
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In the diagram, C2 = 1/5 of coil of C1. If input voltage is 1200 V, find output V. Give reason for laminating the core .
[caption id="attachment_13805" align="alignnone" width="300"] given diagram[/caption]
Given primary voltage = 1200 V
Ns = 1/5 of Np
Secondary voltage = ??
We have,
\(\frac{Vp}{Vs}=\frac{Np}{Ns}\)
\(\frac{1200}{Vs}=5\)
Vs = 240 V
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