Here, primary turns (Np) = 600
PRIMARY EMF (Vp) = 220 V
secondaryturns (Ns) = ?
secondary emf ( Vs ) = 60 V
by using the formula,
\(\frac{Vp}{Vs}=\frac{Np}{Ns}\)
\(\frac{220}{Vs}=\frac{600}{Ns}\)
Ns = 163.63
Ns must be 164 turns.
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In a transformer, the turn in primary coil is 600 and its emf is 220 V. What will be the number of turns in secondary winding, 60V.
Here, primary turns (Np) = 600
PRIMARY EMF (Vp) = 220 V
secondaryturns (Ns) = ?
secondary emf ( Vs ) = 60 V
by using the formula,
\(\frac{Vp}{Vs}=\frac{Np}{Ns}\)
\(\frac{220}{Vs}=\frac{600}{Ns}\)
Ns = 163.63
Ns must be 164 turns.
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