If the median of the following data is 19, find the value of p
Age in Years | 6 - 12 | 12 - 18 | 18 - 24 | 24 - 30 | 30 - 36 | 36 - 42 |
No. of Students | 4 | 10 | p | 4 | 3 | 3 |
1 Answer
Solution:
Preparing the cumulative frequency table to calculate median from the given data, we get
Age in Years X |
No. of students f |
Cumulative frequency cf |
6 - 12 | 4 | 4 |
12 - 18 | 10 | 14 |
18 - 24 | p | 14+p |
24 - 30 | 4 | 18+p |
30 - 36 | 3 | 21+p |
36 - 42 | 3 | 24+p |
N = 24 + p |
Here, median (Md) = 19 lies in (18 - 24)th class
∴ Median class = 18 - 24
Median (Md) = \(L+\frac{{\displaystyle\frac N2}-cf}f\times i\)
Where,
L = 18, \(\frac N2=\frac{24+p}2\), cf = 14, f = p, i = 6
∴ \(19=18+\frac{\left({\displaystyle\frac{24+p}2}-14\right)}p\times6\)
Or, \(19-18=\left(\frac{24+p-28}2\times\frac1p\right)\times6\)
Or, \(1=\frac{3\left(p-4\right)}4\)
Or, p = 3p - 12
Or, 2p = 12
Or, p = 6
Hence the required value of p is 6
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