Solution:
sin9θ - sinθ = 0
⇒ 2cos5θ - sin4θ = 0
⇒ [2sin4θ.cosθ - sin4θ = 0 ]
Either, sin4θ = 0
⇒ 4θ = nπ
⇒ θ = \(\frac{n\pi}4\)
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If the value of sin9θ = sinθ then what is the value of θ ?
Solution:
sin9θ - sinθ = 0
⇒ 2cos5θ - sin4θ = 0
⇒ [2sin4θ.cosθ - sin4θ = 0 ]
Either, sin4θ = 0
⇒ 4θ = nπ
⇒ θ = \(\frac{n\pi}4\)
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