The value of k for which the one root of the equation \(3x^2+7x+6-k=0\) is equal to zero is
- k=3
- k=6
- k=2
- k=-5
1 Answer
Solution:
Let α and β be two roots.
Then one root (α) = 0, [Given]
So, \(\alpha\beta=0,\;\frac ca=0\;or,\frac{6-k}3=0\)
∴ k = 6
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