Let, the event of getting a face card be F.
And the event of getting ace of spades be C.
Then, n(S) = 52, n(F) = 12 and n(C) = 1
To find, P(F∪C)
Here, F and C are mutually exclusive events.
Then, by formula
P(F∪C) = P(F) + P(C)
= \(\frac{n(F)}{n(S)}+\frac{n(C)}{n(S)}\)
= \(\frac{12}{52}+\frac1{52}\)
= \(\frac{12+1}{52}\)
= \(\frac{13}{52}\)
= \(\frac14\)
Therefore, the probability of getting a face card or an ace of spades is \(\frac14\).