In the given solid triangular prism, if PQ ⊥ QR, PQ = 8 cm and RR' = 15 cm, find the lateral surface area of the prism
1 Answer
Given,
In a triangular based prism,
PQ ⊥ RQ, PQ = 8 cm, QR = 6 cm and RR' = 15 cm
To find:
Lateral surface area of the prism (LSA)
Here, In the right angled triangle PQR,
PR = \(\sqrt{PQ^2+QR^2}\)
= \(\sqrt{8^2+6^2}\)
= \(\sqrt{64+36}\)
= \(\sqrt{100}\)
= 10 cm
∴ Perimeter of the triangular base = PQ + QR + PR = 8 cm + 6 cm + 10 cm = 24 cm
Now, by formula
Lateral surface area of the prism (LSA) = perimeter of base x height
= 24 cm x 15 cm
= 360 cm2 is the required answer.
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