**Solution:**

We have,

\(F=\frac{Gm_1m_2}{d^2}\) ----------------- (i)

Or, \(G=\frac{Fd^2}{m_1m_2}\)

Where, F = force and d = distance, m_{1} and m_{2} = masses of two bodies.

Dimension of F = [MLT^{-2}],

dimension of d = [L]

dimension of m = [M]

∴ Dimension of \(G=\frac{\left[MLT^{-2}\times L^2\right]}{\left[M\times M\right]}\)

\(\left[M^{-1}L^3T^{-2}\right]\)