Solution

Given,

First resonance length (l₁) = 18 cm
Second resonance length (l₂) = 56 cm
Frequency (f) = 480 Hz
Velocity of sound (v) = ?
End correction (e) = ?

We have,

v = 2f(l₂ - l₁)
   = 2 x 480 (0.56 - 0.18)
   = 364.8 m/s

Now, end correction is

\(e=\frac{l_2-3l_1}2=\frac{0.56-3\ast0.18}2=0.01\) m