Here, V1= 220 V
I1 = 6A
Time t = 1 day = 24 hrs
Now the electricity consumed will be
= I1 * V1 * t
= 6 * 220 * 24
= 31680 wh
= 31680 / 1000
= 31.68 kwh
So, electrcity consumed in a day = 31.68 kwh
Again, we have 1 kwh = 3.6 * 106 Joule
So, electricity consumed in 1 day in joule = 31.68 * 3.6 * 106 J
= 1.14 * 108 J