Given ,
volume of iceberg vo = (50 * 30 * 20 )cm3
= (0.5 * 0.3 * 0.2 ) m 3
= 0.03 m3
density of ice do = 900
density of water dl = 1000
now for flotation of ice we know the formula,
vo do g = vl dl g
vl = 27 / 1000
vl = 0.027 m 3
Here the volume of iceberg inside water = volume of liquid displaced vl
= 0.027 m 3
so the fraction of ice berg in the water must be 0.027/ 0.03 = 9/10
Also fraction of ice inside water surface = 1 -9/10
=1/10
Again, mass of the water displaced = vl * dl = 0.027 * 1000
= 27 kg
hence, mass of water displaced is 27 kg and portion of ice above water surface is 1/10 th of total volume of iceberg.