Solution:
Given,
Uniform acceleration (a) = 8 m/s2
TIme (t) = 4 seconds
Iniital velocity (u) = 0 [ because the body starts from the rest ]
Distance covered (s) = ?
We have, using the second equation of motion
\(s=ut+\frac12at^2\)
Or, \(s=0\times4+\frac128\times\left(4\right)^2\)
Or, \(s=\frac128\times16\)
∴ s= 64 m
Hence, the body covers 64 m in 4 seconds.