Given,
\(\begin{pmatrix}x+y&0\\2x&7\end{pmatrix}=\begin{pmatrix}5&0\\4&7\end{pmatrix}\)
So, x+y=5 ⇒ y=3
And, 2x=4 ⇒ x=2
Hence (x,y) = (2,3)
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Given,
\(\begin{pmatrix}x+y&0\\2x&7\end{pmatrix}=\begin{pmatrix}5&0\\4&7\end{pmatrix}\)
So, x+y=5 ⇒ y=3
And, 2x=4 ⇒ x=2
Hence (x,y) = (2,3)
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